ASVAB Math Knowledge Practice Test 480913

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -5b - 6b = b - 2y + 4 for b in terms of y.

-\(\frac{2}{3}\)y - \(\frac{2}{3}\)
\(\frac{3}{4}\)y + \(\frac{1}{6}\)
-2\(\frac{1}{5}\)y - 1
-4y - \(\frac{1}{2}\)