ASVAB Math Knowledge Practice Test 481138 Results

Your Results Global Average
Questions 5 5
Correct 0 2.90
Score 0% 58%

Review

1

What is 5a8 - 4a8?

73% Answer Correctly
20a16
a816
1a8
9a16

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

5a8 - 4a8 = 1a8


2

Solve for z:
-5z - 1 > \( \frac{z}{7} \)

44% Answer Correctly
z > -\(\frac{3}{10}\)
z > 1\(\frac{3}{11}\)
z > -\(\frac{7}{36}\)
z > \(\frac{1}{2}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

-5z - 1 > \( \frac{z}{7} \)
7 x (-5z - 1) > z
(7 x -5z) + (7 x -1) > z
-35z - 7 > z
-35z - 7 - z > 0
-35z - z > 7
-36z > 7
z > \( \frac{7}{-36} \)
z > -\(\frac{7}{36}\)


3

The dimensions of this trapezoid are a = 6, b = 8, c = 7, d = 9, and h = 5. What is the area?

50% Answer Correctly
18
30
42\(\frac{1}{2}\)
16\(\frac{1}{2}\)

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(8 + 9)(5)
a = ½(17)(5)
a = ½(85) = \( \frac{85}{2} \)
a = 42\(\frac{1}{2}\)


4

This diagram represents two parallel lines with a transversal. If b° = 149, what is the value of a°?

73% Answer Correctly
28
40
161
31

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with b° = 149, the value of a° is 31.


5

Solve for y:
y2 + 2y - 28 = -4y - 1

48% Answer Correctly
9 or -7
3 or -9
1 or -7
9 or -4

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

y2 + 2y - 28 = -4y - 1
y2 + 2y - 28 + 1 = -4y
y2 + 2y + 4y - 27 = 0
y2 + 6y - 27 = 0

Next, factor the quadratic equation:

y2 + 6y - 27 = 0
(y - 3)(y + 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (y - 3) or (y + 9) must equal zero:

If (y - 3) = 0, y must equal 3
If (y + 9) = 0, y must equal -9

So the solution is that y = 3 or -9