| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.73 |
| Score | 0% | 55% |
Solve for b:
b - 5 > \( \frac{b}{-8} \)
| b > 4\(\frac{4}{9}\) | |
| b > \(\frac{12}{13}\) | |
| b > -\(\frac{16}{21}\) | |
| b > 3\(\frac{3}{7}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
b - 5 > \( \frac{b}{-8} \)
-8 x (b - 5) > b
(-8 x b) + (-8 x -5) > b
-8b + 40 > b
-8b + 40 - b > 0
-8b - b > -40
-9b > -40
b > \( \frac{-40}{-9} \)
b > 4\(\frac{4}{9}\)
If the length of AB equals the length of BD, point B __________ this line segment.
midpoints |
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bisects |
|
intersects |
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trisects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
If side a = 8, side b = 1, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{26} \) | |
| \( \sqrt{65} \) | |
| \( \sqrt{52} \) | |
| \( \sqrt{90} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 82 + 12
c2 = 64 + 1
c2 = 65
c = \( \sqrt{65} \)
If a = c = 1, b = d = 5, and the blue angle = 69°, what is the area of this parallelogram?
| 10 | |
| 5 | |
| 9 | |
| 15 |
The area of a parallelogram is equal to its length x width:
a = l x w
a = a x b
a = 1 x 5
a = 5
Solve for x:
8x + 2 > -1 + 2x
| x > -1 | |
| x > \(\frac{5}{8}\) | |
| x > \(\frac{2}{9}\) | |
| x > -\(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
8x + 2 > -1 + 2x
8x > -1 + 2x - 2
8x - 2x > -1 - 2
6x > -3
x > \( \frac{-3}{6} \)
x > -\(\frac{1}{2}\)