ASVAB Math Knowledge Practice Test 482498 Results

Your Results Global Average
Questions 5 5
Correct 0 2.91
Score 0% 58%

Review

1

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

61% Answer Correctly

obtuse, acute

supplementary, vertical

acute, obtuse

vertical, supplementary


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


2

If angle a = 44° and angle b = 66° what is the length of angle c?

71% Answer Correctly
100°
70°
88°
102°

Solution

The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 44° - 66° = 70°


3

Simplify (6a)(3ab) + (5a2)(7b).

66% Answer Correctly
53ab2
17ab2
53a2b
108ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(3ab) + (5a2)(7b)
(6 x 3)(a x a x b) + (5 x 7)(a2 x b)
(18)(a1+1 x b) + (35)(a2b)
18a2b + 35a2b
53a2b


4

On this circle, line segment CD is the:

46% Answer Correctly

radius

diameter

chord

circumference


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

Solve for z:
6z - 5 = \( \frac{z}{-2} \)

46% Answer Correctly
-\(\frac{28}{29}\)
-\(\frac{1}{4}\)
-7\(\frac{1}{2}\)
\(\frac{10}{13}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

6z - 5 = \( \frac{z}{-2} \)
-2 x (6z - 5) = z
(-2 x 6z) + (-2 x -5) = z
-12z + 10 = z
-12z + 10 - z = 0
-12z - z = -10
-13z = -10
z = \( \frac{-10}{-13} \)
z = \(\frac{10}{13}\)