ASVAB Math Knowledge Practice Test 482758

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4b - 4b = -2b + 9z - 8 for b in terms of z.

\(\frac{1}{13}\)z + \(\frac{4}{13}\)
2\(\frac{1}{6}\)z - 1\(\frac{1}{3}\)
2\(\frac{1}{2}\)z + 3\(\frac{1}{2}\)
-1\(\frac{1}{12}\)z - \(\frac{5}{12}\)