| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.15 |
| Score | 0% | 63% |
What is 4a - 2a?
| a2 | |
| 2a | |
| 2a2 | |
| 8a |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
4a - 2a = 2a
If the area of this square is 4, what is the length of one of the diagonals?
| 6\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| 5\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)
Breaking apart a quadratic expression into a pair of binomials is called:
deconstructing |
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factoring |
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normalizing |
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squaring |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
Which of the following is not required to define the slope-intercept equation for a line?
x-intercept |
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slope |
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\({\Delta y \over \Delta x}\) |
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y-intercept |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.
Factor y2 + 3y + 2
| (y - 1)(y - 2) | |
| (y + 1)(y - 2) | |
| (y - 1)(y + 2) | |
| (y + 1)(y + 2) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 2 as well and sum (Inside, Outside) to equal 3. For this problem, those two numbers are 1 and 2. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + 3y + 2
y2 + (1 + 2)y + (1 x 2)
(y + 1)(y + 2)