| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.00 |
| Score | 0% | 60% |
Solve -4b + 6b = 8b + 9x + 1 for b in terms of x.
| \(\frac{2}{5}\)x + \(\frac{1}{5}\) | |
| -1\(\frac{2}{3}\)x + 1\(\frac{1}{2}\) | |
| -\(\frac{1}{4}\)x - \(\frac{1}{12}\) | |
| 11x - 6 |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-4b + 6x = 8b + 9x + 1
-4b = 8b + 9x + 1 - 6x
-4b - 8b = 9x + 1 - 6x
-12b = 3x + 1
b = \( \frac{3x + 1}{-12} \)
b = \( \frac{3x}{-12} \) + \( \frac{1}{-12} \)
b = -\(\frac{1}{4}\)x - \(\frac{1}{12}\)
A right angle measures:
360° |
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180° |
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45° |
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90° |
A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.
If the area of this square is 25, what is the length of one of the diagonals?
| 2\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 5\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)
The endpoints of this line segment are at (-2, -2) and (2, 6). What is the slope of this line?
| -2\(\frac{1}{2}\) | |
| -3 | |
| \(\frac{1}{2}\) | |
| 2 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -2) and (2, 6) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(6.0) - (-2.0)}{(2) - (-2)} \) = \( \frac{8}{4} \)When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
acute, obtuse |
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supplementary, vertical |
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obtuse, acute |
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vertical, supplementary |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).