ASVAB Math Knowledge Practice Test 48572 Results

Your Results Global Average
Questions 5 5
Correct 0 2.72
Score 0% 54%

Review

1

Simplify (5a)(4ab) + (2a2)(3b).

66% Answer Correctly
14ab2
26a2b
14a2b
45a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(5a)(4ab) + (2a2)(3b)
(5 x 4)(a x a x b) + (2 x 3)(a2 x b)
(20)(a1+1 x b) + (6)(a2b)
20a2b + 6a2b
26a2b


2

This diagram represents two parallel lines with a transversal. If b° = 169, what is the value of y°?

73% Answer Correctly
169
13
170
39

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with b° = 169, the value of y° is 169.


3

Simplify (2a)(9ab) - (9a2)(5b).

63% Answer Correctly
154a2b
63ab2
63a2b
-27a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(2a)(9ab) - (9a2)(5b)
(2 x 9)(a x a x b) - (9 x 5)(a2 x b)
(18)(a1+1 x b) - (45)(a2b)
18a2b - 45a2b
-27a2b


4

The formula for the area of a circle is which of the following?

24% Answer Correctly

c = π d

c = π r2

c = π r

c = π d2


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


5

Solve for a:
-6a + 9 = \( \frac{a}{-2} \)

46% Answer Correctly
\(\frac{48}{55}\)
1
1\(\frac{7}{11}\)
-\(\frac{9}{32}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-6a + 9 = \( \frac{a}{-2} \)
-2 x (-6a + 9) = a
(-2 x -6a) + (-2 x 9) = a
12a - 18 = a
12a - 18 - a = 0
12a - a = 18
11a = 18
a = \( \frac{18}{11} \)
a = 1\(\frac{7}{11}\)