| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.73 |
| Score | 0% | 75% |
If side x = 15cm, side y = 7cm, and side z = 6cm what is the perimeter of this triangle?
| 28cm | |
| 34cm | |
| 31cm | |
| 37cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 15cm + 7cm + 6cm = 28cm
If side a = 8, side b = 4, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{145} \) | |
| \( \sqrt{80} \) | |
| \( \sqrt{50} \) | |
| \( \sqrt{29} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 82 + 42
c2 = 64 + 16
c2 = 80
c = \( \sqrt{80} \)
Simplify 8a x 4b.
| 32ab | |
| 12ab | |
| 32a2b2 | |
| 32\( \frac{a}{b} \) |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
8a x 4b = (8 x 4) (a x b) = 32ab
This diagram represents two parallel lines with a transversal. If a° = 29, what is the value of d°?
| 151 | |
| 29 | |
| 18 | |
| 145 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with a° = 29, the value of d° is 151.
If c = 3 and x = -2, what is the value of 4c(c - x)?
| 280 | |
| 528 | |
| -27 | |
| 60 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
4c(c - x)
4(3)(3 + 2)
4(3)(5)
(12)(5)
60