ASVAB Math Knowledge Practice Test 485957 Results

Your Results Global Average
Questions 5 5
Correct 0 3.23
Score 0% 65%

Review

1

Solve for y:
-5y - 8 = -9 - 9y

59% Answer Correctly
1\(\frac{2}{7}\)
-\(\frac{3}{4}\)
-1\(\frac{1}{2}\)
-\(\frac{1}{4}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-5y - 8 = -9 - 9y
-5y = -9 - 9y + 8
-5y + 9y = -9 + 8
4y = -1
y = \( \frac{-1}{4} \)
y = -\(\frac{1}{4}\)


2

The dimensions of this cube are height (h) = 5, length (l) = 1, and width (w) = 8. What is the volume?

82% Answer Correctly
24
18
40
405

Solution

The volume of a cube is height x length x width:

v = h x l x w
v = 5 x 1 x 8
v = 40


3

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

60% Answer Correctly

acute, obtuse

supplementary, vertical

vertical, supplementary

obtuse, acute


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


4

Solve for z:
-9z - 8 < -7 + 7z

55% Answer Correctly
z < -\(\frac{1}{3}\)
z < -\(\frac{1}{16}\)
z < 1\(\frac{1}{4}\)
z < 1\(\frac{1}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-9z - 8 < -7 + 7z
-9z < -7 + 7z + 8
-9z - 7z < -7 + 8
-16z < 1
z < \( \frac{1}{-16} \)
z < -\(\frac{1}{16}\)


5

The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?

67% Answer Correctly

h x l x w

2lw x 2wh + 2lh

lw x wh + lh

h2 x l2 x w2


Solution

A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.