ASVAB Math Knowledge Practice Test 486102

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 7b + 8b = 2b - 4z + 7 for b in terms of z.

-2\(\frac{2}{5}\)z + 1\(\frac{2}{5}\)
14z + 3
6\(\frac{1}{2}\)z - 3
-\(\frac{4}{5}\)z - 1\(\frac{2}{5}\)