ASVAB Math Knowledge Practice Test 487904 Results

Your Results Global Average
Questions 5 5
Correct 0 3.68
Score 0% 74%

Review

1

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c2 + a2

a2 - c2

c2 - a2

c - a


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


2

If side x = 11cm, side y = 6cm, and side z = 9cm what is the perimeter of this triangle?

85% Answer Correctly
33cm
25cm
26cm
29cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 11cm + 6cm + 9cm = 26cm


3

A quadrilateral is a shape with __________ sides.

91% Answer Correctly

2

4

5

3


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.


4

If AD = 27 and BD = 25, AB = ?

76% Answer Correctly
2
7
17
11

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 27 - 25
AB = 2


5

If the area of this square is 4, what is the length of one of the diagonals?

68% Answer Correctly
8\( \sqrt{2} \)
7\( \sqrt{2} \)
2\( \sqrt{2} \)
4\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)