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|---|---|---|
| Questions | 5 | 5 |
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For this diagram, the Pythagorean theorem states that b2 = ?
c2 + a2 |
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a2 - c2 |
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c2 - a2 |
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c - a |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
If side x = 11cm, side y = 6cm, and side z = 9cm what is the perimeter of this triangle?
| 33cm | |
| 25cm | |
| 26cm | |
| 29cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 11cm + 6cm + 9cm = 26cm
A quadrilateral is a shape with __________ sides.
2 |
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4 |
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5 |
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3 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.
If AD = 27 and BD = 25, AB = ?
| 2 | |
| 7 | |
| 17 | |
| 11 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDIf the area of this square is 4, what is the length of one of the diagonals?
| 8\( \sqrt{2} \) | |
| 7\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)