ASVAB Math Knowledge Practice Test 488419

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -b + 7b = -4b + 4z + 2 for b in terms of z.

\(\frac{3}{13}\)z - \(\frac{9}{13}\)
-2\(\frac{1}{2}\)z + 1\(\frac{1}{3}\)
-\(\frac{5}{13}\)z - \(\frac{6}{13}\)
-z + \(\frac{2}{3}\)