ASVAB Math Knowledge Practice Test 488767

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -4b - b = -b - 3z + 4 for b in terms of z.

\(\frac{3}{10}\)z - \(\frac{1}{10}\)
\(\frac{2}{3}\)z - 1\(\frac{1}{3}\)
-2\(\frac{1}{6}\)z + 1\(\frac{1}{3}\)
\(\frac{1}{6}\)z + \(\frac{5}{12}\)