When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - 4c = -9c + 3z - 6 for c in terms of z.
| \(\frac{3}{13}\)z - \(\frac{8}{13}\) | |
| 5\(\frac{2}{3}\)z + 2\(\frac{1}{3}\) | |
| -1\(\frac{1}{13}\)z + \(\frac{6}{13}\) | |
| \(\frac{7}{12}\)z - \(\frac{1}{2}\) |