ASVAB Math Knowledge Practice Test 48927

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6a - 4a = 4a + 3y - 1 for a in terms of y.

2\(\frac{1}{2}\)y + \(\frac{1}{2}\)
-\(\frac{3}{5}\)y - 1\(\frac{2}{5}\)
\(\frac{4}{7}\)y - 1\(\frac{2}{7}\)
-\(\frac{7}{10}\)y + \(\frac{1}{10}\)