When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve c + 3c = -8c + 4x + 3 for c in terms of x.
| -\(\frac{1}{16}\)x + \(\frac{3}{8}\) | |
| -\(\frac{3}{5}\)x - \(\frac{4}{5}\) | |
| \(\frac{3}{5}\)x + \(\frac{1}{5}\) | |
| \(\frac{1}{9}\)x + \(\frac{1}{3}\) |