| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.25 |
| Score | 0% | 65% |
Solve for x:
3x - 7 = \( \frac{x}{1} \)
| 1\(\frac{1}{23}\) | |
| -\(\frac{3}{7}\) | |
| 3\(\frac{1}{2}\) | |
| -6\(\frac{2}{3}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
3x - 7 = \( \frac{x}{1} \)
1 x (3x - 7) = x
(1 x 3x) + (1 x -7) = x
3x - 7 = x
3x - 7 - x = 0
3x - x = 7
2x = 7
x = \( \frac{7}{2} \)
x = 3\(\frac{1}{2}\)
Simplify (7a)(5ab) + (8a2)(6b).
| 13ab2 | |
| 83a2b | |
| -13ab2 | |
| 168ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(7a)(5ab) + (8a2)(6b)
(7 x 5)(a x a x b) + (8 x 6)(a2 x b)
(35)(a1+1 x b) + (48)(a2b)
35a2b + 48a2b
83a2b
If BD = 21 and AD = 27, AB = ?
| 6 | |
| 14 | |
| 5 | |
| 13 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDA cylinder with a radius (r) and a height (h) has a surface area of:
π r2h |
|
π r2h2 |
|
4π r2 |
|
2(π r2) + 2π rh |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
Simplify 6a x 2b.
| 12ab | |
| 12a2b2 | |
| 12\( \frac{b}{a} \) | |
| 8ab |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
6a x 2b = (6 x 2) (a x b) = 12ab