When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 5c = 3c + 2z - 3 for c in terms of z.
| -\(\frac{2}{3}\)z - \(\frac{5}{6}\) | |
| 1\(\frac{1}{5}\)z - 1\(\frac{3}{5}\) | |
| -\(\frac{3}{5}\)z - \(\frac{3}{5}\) | |
| -\(\frac{1}{3}\)z - 1\(\frac{1}{3}\) |