| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.06 |
| Score | 0% | 61% |
If the area of this square is 64, what is the length of one of the diagonals?
| 8\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) | |
| 9\( \sqrt{2} \) | |
| 5\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{64} \) = 8
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 82 + 82
c2 = 128
c = \( \sqrt{128} \) = \( \sqrt{64 x 2} \) = \( \sqrt{64} \) \( \sqrt{2} \)
c = 8\( \sqrt{2} \)
On this circle, a line segment connecting point A to point D is called:
radius |
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chord |
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circumference |
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diameter |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
A trapezoid is a quadrilateral with one set of __________ sides.
equal length |
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right angle |
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equal angle |
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parallel |
A trapezoid is a quadrilateral with one set of parallel sides.
If side a = 6, side b = 7, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{65} \) | |
| \( \sqrt{52} \) | |
| \( \sqrt{145} \) | |
| \( \sqrt{85} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 62 + 72
c2 = 36 + 49
c2 = 85
c = \( \sqrt{85} \)
Solve for z:
z2 - 25 = 0
| 5 or -5 | |
| 7 or -7 | |
| 5 or -8 | |
| 9 or -6 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
z2 - 25 = 0
(z - 5)(z + 5) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 5) or (z + 5) must equal zero:
If (z - 5) = 0, z must equal 5
If (z + 5) = 0, z must equal -5
So the solution is that z = 5 or -5