ASVAB Math Knowledge Practice Test 491365

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -4c - 6c = 2c - 2z + 3 for c in terms of z.

z - \(\frac{1}{2}\)
-\(\frac{2}{3}\)z - \(\frac{1}{2}\)
7z + 2\(\frac{1}{2}\)
-1\(\frac{2}{5}\)z + 1