When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 8c = c - 5x - 9 for c in terms of x.
| 2\(\frac{1}{3}\)x - 2\(\frac{2}{3}\) | |
| -2\(\frac{3}{5}\)x - 1\(\frac{4}{5}\) | |
| 4x + 6 | |
| -3x + 1\(\frac{3}{4}\) |