When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 9c = -4c + 2z + 8 for c in terms of z.
| -\(\frac{7}{8}\)z + 1 | |
| -\(\frac{1}{4}\)z - 1\(\frac{1}{2}\) | |
| 2\(\frac{1}{6}\)z - \(\frac{1}{2}\) | |
| \(\frac{1}{4}\)z - \(\frac{1}{6}\) |