| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.59 |
| Score | 0% | 52% |
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h |
|
π r2h2 |
|
2(π r2) + 2π rh |
|
4π r2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
Solve -6c + 8c = -7c - 4z - 5 for c in terms of z.
| z - 3 | |
| -2\(\frac{1}{2}\)z - 1 | |
| 1\(\frac{3}{10}\)z - \(\frac{9}{10}\) | |
| -12z - 5 |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
-6c + 8z = -7c - 4z - 5
-6c = -7c - 4z - 5 - 8z
-6c + 7c = -4z - 5 - 8z
c = -12z - 5
Solve for z:
z2 + z + 4 = 4z + 2
| 9 or 3 | |
| -2 or -9 | |
| 1 or 2 | |
| -4 or -5 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
z2 + z + 4 = 4z + 2
z2 + z + 4 - 2 = 4z
z2 + z - 4z + 2 = 0
z2 - 3z + 2 = 0
Next, factor the quadratic equation:
z2 - 3z + 2 = 0
(z - 1)(z - 2) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 1) or (z - 2) must equal zero:
If (z - 1) = 0, z must equal 1
If (z - 2) = 0, z must equal 2
So the solution is that z = 1 or 2
Simplify (y - 2)(y + 2)
| y2 + 4y + 4 | |
| y2 - 4 | |
| y2 - 4y + 4 | |
| 92 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y - 2)(y + 2)
(y x y) + (y x 2) + (-2 x y) + (-2 x 2)
y2 + 2y - 2y - 4
y2 - 4
Solve for z:
z2 - 1 = 0
| 1 or -1 | |
| -3 or -4 | |
| -7 or -9 | |
| -1 or -5 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
z2 - 1 = 0
(z - 1)(z + 1) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 1) or (z + 1) must equal zero:
If (z - 1) = 0, z must equal 1
If (z + 1) = 0, z must equal -1
So the solution is that z = 1 or -1