ASVAB Math Knowledge Practice Test 496873

Question 5 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 7a + 3a = -7a - 2z - 1 for a in terms of z.

6z + 3
-\(\frac{5}{14}\)z - \(\frac{1}{14}\)
1\(\frac{1}{6}\)z - \(\frac{1}{4}\)
z + 1