ASVAB Math Knowledge Practice Test 497871

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 8c + c = c + x - 2 for c in terms of x.

-\(\frac{5}{7}\)x + \(\frac{9}{14}\)
-4x + 3
-4\(\frac{1}{3}\)x + 1\(\frac{2}{3}\)
x - \(\frac{2}{7}\)