| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.86 |
| Score | 0% | 57% |
A cylinder with a radius (r) and a height (h) has a surface area of:
2(π r2) + 2π rh |
|
π r2h |
|
π r2h2 |
|
4π r2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
Simplify (6a)(5ab) + (9a2)(4b).
| 66ab2 | |
| -6a2b | |
| 143a2b | |
| 66a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(6a)(5ab) + (9a2)(4b)
(6 x 5)(a x a x b) + (9 x 4)(a2 x b)
(30)(a1+1 x b) + (36)(a2b)
30a2b + 36a2b
66a2b
If a = 3, b = 6, c = 3, and d = 5, what is the perimeter of this quadrilateral?
| 26 | |
| 24 | |
| 17 | |
| 15 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 3 + 6 + 3 + 5
p = 17
Solve -4c - 3c = -5c - z - 6 for c in terms of z.
| 3\(\frac{1}{2}\)z - 3 | |
| -7\(\frac{1}{2}\)z + \(\frac{1}{2}\) | |
| z - \(\frac{1}{2}\) | |
| 2z - 6 |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
-4c - 3z = -5c - z - 6
-4c = -5c - z - 6 + 3z
-4c + 5c = -z - 6 + 3z
c = 2z - 6
For this diagram, the Pythagorean theorem states that b2 = ?
c2 - a2 |
|
c - a |
|
a2 - c2 |
|
c2 + a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)