ASVAB Math Knowledge Practice Test 500127

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4a - 3a = a - 9z + 6 for a in terms of z.

-2z + 2
3z + 2
-2\(\frac{1}{3}\)z + \(\frac{2}{3}\)
-1\(\frac{1}{2}\)z + 4\(\frac{1}{2}\)