When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c + c = 4c + 3y - 3 for c in terms of y.
| -2y - 3\(\frac{1}{2}\) | |
| y - 4 | |
| -\(\frac{1}{16}\)y + \(\frac{9}{16}\) | |
| \(\frac{2}{5}\)y - \(\frac{3}{5}\) |