ASVAB Math Knowledge Practice Test 502256

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 5a + 4a = 3a + 6z + 9 for a in terms of z.

z + 4\(\frac{1}{2}\)
\(\frac{1}{2}\)z - 1\(\frac{1}{4}\)
-1\(\frac{4}{7}\)z - \(\frac{5}{7}\)
\(\frac{4}{11}\)z - \(\frac{2}{11}\)