ASVAB Math Knowledge Practice Test 502502 Results

Your Results Global Average
Questions 5 5
Correct 0 2.90
Score 0% 58%

Review

1

Find the value of c:
6c + y = -8
5c - y = 5

42% Answer Correctly
-\(\frac{1}{22}\)
2\(\frac{6}{13}\)
-\(\frac{3}{11}\)
\(\frac{2}{7}\)

Solution

You need to find the value of c so solve the first equation in terms of y:

6c + y = -8
y = -8 - 6c

then substitute the result (-8 - 6c) into the second equation:

5c - 1(-8 - 6c) = 5
5c + (-1 x -8) + (-1 x -6c) = 5
5c + 8 + 6c = 5
5c + 6c = 5 - 8
11c = -3
c = \( \frac{-3}{11} \)
c = -\(\frac{3}{11}\)


2

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

midpoints

intersects

bisects

trisects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


3

A right angle measures:

90% Answer Correctly

360°

45°

90°

180°


Solution

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.


4

If side a = 8, side b = 1, what is the length of the hypotenuse of this right triangle?

63% Answer Correctly
\( \sqrt{53} \)
\( \sqrt{74} \)
\( \sqrt{117} \)
\( \sqrt{65} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 82 + 12
c2 = 64 + 1
c2 = 65
c = \( \sqrt{65} \)


5

The dimensions of this cylinder are height (h) = 4 and radius (r) = 4. What is the surface area?

48% Answer Correctly
64π
56π
16π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(42) + 2π(4 x 4)
sa = 2π(16) + 2π(16)
sa = (2 x 16)π + (2 x 16)π
sa = 32π + 32π
sa = 64π