| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.32 |
| Score | 0% | 66% |
On this circle, line segment AB is the:
diameter |
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circumference |
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chord |
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radius |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Solve 7a - 9a = 9a - 5x - 2 for a in terms of x.
| -2x + 1 | |
| -1\(\frac{1}{11}\)x + \(\frac{8}{11}\) | |
| -3\(\frac{1}{3}\)x - 1\(\frac{1}{3}\) | |
| \(\frac{1}{7}\)x - 1\(\frac{1}{7}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
7a - 9x = 9a - 5x - 2
7a = 9a - 5x - 2 + 9x
7a - 9a = -5x - 2 + 9x
-2a = 4x - 2
a = \( \frac{4x - 2}{-2} \)
a = \( \frac{4x}{-2} \) + \( \frac{-2}{-2} \)
a = -2x + 1
If the area of this square is 36, what is the length of one of the diagonals?
| 6\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 5\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{36} \) = 6
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 62 + 62
c2 = 72
c = \( \sqrt{72} \) = \( \sqrt{36 x 2} \) = \( \sqrt{36} \) \( \sqrt{2} \)
c = 6\( \sqrt{2} \)
Order the following types of angle from least number of degrees to most number of degrees.
right, obtuse, acute |
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acute, obtuse, right |
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acute, right, obtuse |
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right, acute, obtuse |
An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.
If side x = 9cm, side y = 12cm, and side z = 7cm what is the perimeter of this triangle?
| 27cm | |
| 18cm | |
| 28cm | |
| 33cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 9cm + 12cm + 7cm = 28cm