ASVAB Math Knowledge Practice Test 504841

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6b - 2b = -4b + 5z + 9 for b in terms of z.

\(\frac{7}{10}\)z + \(\frac{9}{10}\)
\(\frac{3}{8}\)z + \(\frac{1}{4}\)
-1\(\frac{1}{3}\)z + 2
-1\(\frac{5}{6}\)z + \(\frac{1}{2}\)