ASVAB Math Knowledge Practice Test 505212 Results

Your Results Global Average
Questions 5 5
Correct 0 3.38
Score 0% 68%

Review

1

If the base of this triangle is 2 and the height is 9, what is the area?

58% Answer Correctly
9
32\(\frac{1}{2}\)
36
65

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 2 x 9 = \( \frac{18}{2} \) = 9


2

Breaking apart a quadratic expression into a pair of binomials is called:

74% Answer Correctly

factoring

deconstructing

normalizing

squaring


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.


3

A trapezoid is a quadrilateral with one set of __________ sides.

69% Answer Correctly

equal angle

right angle

parallel

equal length


Solution

A trapezoid is a quadrilateral with one set of parallel sides.


4

If c = 6 and y = 2, what is the value of -8c(c - y)?

68% Answer Correctly
-432
64
-192
88

Solution

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

-8c(c - y)
-8(6)(6 - 2)
-8(6)(4)
(-48)(4)
-192


5

If the area of this square is 16, what is the length of one of the diagonals?

68% Answer Correctly
4\( \sqrt{2} \)
2\( \sqrt{2} \)
7\( \sqrt{2} \)
5\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{16} \) = 4

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 42 + 42
c2 = 32
c = \( \sqrt{32} \) = \( \sqrt{16 x 2} \) = \( \sqrt{16} \) \( \sqrt{2} \)
c = 4\( \sqrt{2} \)