To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-2y + 3 < \( \frac{y}{3} \)
3 x (-2y + 3) < y
(3 x -2y) + (3 x 3) < y
-6y + 9 < y
-6y + 9 - y < 0
-6y - y < -9
-7y < -9
y < \( \frac{-9}{-7} \)
y < 1\(\frac{2}{7}\)

A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

b² + 16b + 63 = 0
(b + 7)(b + 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (b + 7) or (b + 9) must equal zero:

If (b + 7) = 0, b must equal -7
If (b + 9) = 0, b must equal -9

So the solution is that b = -7 or -9

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses.

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

z² + 5z - 22 = -2z - 4
z² + 5z - 22 + 4 = -2z
z² + 5z + 2z - 18 = 0
z² + 7z - 18 = 0

Next, factor the quadratic equation:

z² + 7z - 18 = 0
(z - 2)(z + 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 2) or (z + 9) must equal zero:

If (z - 2) = 0, z must equal 2
If (z + 9) = 0, z must equal -9

So the solution is that z = 2 or -9