ASVAB Math Knowledge Practice Test 507897 Results

Your Results Global Average
Questions 5 5
Correct 0 2.95
Score 0% 59%

Review

1

Solve for b:
4b - 5 < 7 - 7b

55% Answer Correctly
b < 1\(\frac{1}{11}\)
b < 8
b < 1\(\frac{1}{3}\)
b < -1\(\frac{1}{7}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

4b - 5 < 7 - 7b
4b < 7 - 7b + 5
4b + 7b < 7 + 5
11b < 12
b < \( \frac{12}{11} \)
b < 1\(\frac{1}{11}\)


2

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

midpoints

intersects

trisects

bisects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


3

A quadrilateral is a shape with __________ sides.

90% Answer Correctly

5

3

4

2


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.


4

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

chord

circumference

diameter

radius


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

Solve for y:
y2 - 4 = 0

58% Answer Correctly
4 or -1
2 or -2
8 or -2
-9 or -9

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

y2 - 4 = 0
(y - 2)(y + 2) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (y - 2) or (y + 2) must equal zero:

If (y - 2) = 0, y must equal 2
If (y + 2) = 0, y must equal -2

So the solution is that y = 2 or -2