ASVAB Math Knowledge Practice Test 508377 Results

Your Results Global Average
Questions 5 5
Correct 0 2.81
Score 0% 56%

Review

1

Solve for y:
2y + 4 = 3 + 4y

59% Answer Correctly
\(\frac{1}{3}\)
-\(\frac{2}{3}\)
\(\frac{1}{2}\)
-1\(\frac{1}{8}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

2y + 4 = 3 + 4y
2y = 3 + 4y - 4
2y - 4y = 3 - 4
-2y = -1
y = \( \frac{-1}{-2} \)
y = \(\frac{1}{2}\)


2

Solve for y:
y2 - y - 10 = -5y - 5

48% Answer Correctly
-1 or -2
1 or -5
-4 or -4
5 or -6

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

y2 - y - 10 = -5y - 5
y2 - y - 10 + 5 = -5y
y2 - y + 5y - 5 = 0
y2 + 4y - 5 = 0

Next, factor the quadratic equation:

y2 + 4y - 5 = 0
(y - 1)(y + 5) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (y - 1) or (y + 5) must equal zero:

If (y - 1) = 0, y must equal 1
If (y + 5) = 0, y must equal -5

So the solution is that y = 1 or -5


3

If side a = 8, side b = 6, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{52} \)
\( \sqrt{41} \)
10
\( \sqrt{82} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 82 + 62
c2 = 64 + 36
c2 = 100
c = \( \sqrt{100} \)
c = 10


4

Simplify (6a)(9ab) - (8a2)(4b).

62% Answer Correctly
180a2b
86a2b
22a2b
86ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(9ab) - (8a2)(4b)
(6 x 9)(a x a x b) - (8 x 4)(a2 x b)
(54)(a1+1 x b) - (32)(a2b)
54a2b - 32a2b
22a2b


5

The dimensions of this cylinder are height (h) = 6 and radius (r) = 6. What is the surface area?

48% Answer Correctly
144π
140π
130π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(62) + 2π(6 x 6)
sa = 2π(36) + 2π(36)
sa = (2 x 36)π + (2 x 36)π
sa = 72π + 72π
sa = 144π