ASVAB Math Knowledge Practice Test 508512

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6b + 4b = -7b + 2z - 5 for b in terms of z.

1\(\frac{1}{3}\)z - \(\frac{1}{3}\)
-\(\frac{1}{5}\)z - \(\frac{1}{5}\)
1\(\frac{5}{7}\)z - \(\frac{1}{7}\)
-2z - 5