| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.17 |
| Score | 0% | 63% |
Solve for c:
9c - 6 < 1 - 3c
| c < -6 | |
| c < \(\frac{7}{12}\) | |
| c < \(\frac{1}{2}\) | |
| c < -1\(\frac{1}{8}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
9c - 6 < 1 - 3c
9c < 1 - 3c + 6
9c + 3c < 1 + 6
12c < 7
c < \( \frac{7}{12} \)
c < \(\frac{7}{12}\)
What is 5a - 5a?
| 25a | |
| a2 | |
| 0a | |
| 0 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
5a - 5a = 0a
If angle a = 41° and angle b = 28° what is the length of angle d?
| 153° | |
| 119° | |
| 139° | |
| 159° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 41° - 28° = 111°
So, d° = 28° + 111° = 139°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 41° = 139°
Which types of triangles will always have at least two sides of equal length?
equilateral and right |
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equilateral and isosceles |
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equilateral, isosceles and right |
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isosceles and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
Breaking apart a quadratic expression into a pair of binomials is called:
factoring |
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normalizing |
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squaring |
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deconstructing |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.