| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.69 |
| Score | 0% | 74% |
This diagram represents two parallel lines with a transversal. If y° = 147, what is the value of b°?
| 147 | |
| 150 | |
| 38 | |
| 36 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with y° = 147, the value of b° is 147.
What is 5a + 2a?
| 7 | |
| 10a | |
| 10a2 | |
| 7a |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
5a + 2a = 7a
Order the following types of angle from least number of degrees to most number of degrees.
acute, obtuse, right |
|
right, obtuse, acute |
|
acute, right, obtuse |
|
right, acute, obtuse |
An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
exponents |
|
pairs |
|
addition |
|
division |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve for c:
c - 1 < \( \frac{c}{-6} \)
| c < 8 | |
| c < 1\(\frac{9}{23}\) | |
| c < 3\(\frac{5}{17}\) | |
| c < \(\frac{6}{7}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
c - 1 < \( \frac{c}{-6} \)
-6 x (c - 1) < c
(-6 x c) + (-6 x -1) < c
-6c + 6 < c
-6c + 6 - c < 0
-6c - c < -6
-7c < -6
c < \( \frac{-6}{-7} \)
c < \(\frac{6}{7}\)