ASVAB Math Knowledge Practice Test 508644 Results

Your Results Global Average
Questions 5 5
Correct 0 3.69
Score 0% 74%

Review

1

This diagram represents two parallel lines with a transversal. If y° = 147, what is the value of b°?

73% Answer Correctly
147
150
38
36

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with y° = 147, the value of b° is 147.


2

What is 5a + 2a?

81% Answer Correctly
7
10a
10a2
7a

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

5a + 2a = 7a


3

Order the following types of angle from least number of degrees to most number of degrees.

76% Answer Correctly

acute, obtuse, right

right, obtuse, acute

acute, right, obtuse

right, acute, obtuse


Solution

An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.


4

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

92% Answer Correctly

exponents

pairs

addition

division


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


5

Solve for c:
c - 1 < \( \frac{c}{-6} \)

45% Answer Correctly
c < 8
c < 1\(\frac{9}{23}\)
c < 3\(\frac{5}{17}\)
c < \(\frac{6}{7}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

c - 1 < \( \frac{c}{-6} \)
-6 x (c - 1) < c
(-6 x c) + (-6 x -1) < c
-6c + 6 < c
-6c + 6 - c < 0
-6c - c < -6
-7c < -6
c < \( \frac{-6}{-7} \)
c < \(\frac{6}{7}\)