ASVAB Math Knowledge Practice Test 508884 Results

Your Results Global Average
Questions 5 5
Correct 0 2.97
Score 0% 59%

Review

1

On this circle, line segment AB is the:

70% Answer Correctly

diameter

circumference

chord

radius


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


2

Which types of triangles will always have at least two sides of equal length?

53% Answer Correctly

equilateral and isosceles

isosceles and right

equilateral and right

equilateral, isosceles and right


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


3

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

all interior angles are right angles

the area is length x width

the lengths of all sides are equal

the perimeter is the sum of the lengths of all four sides


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


4

A cylinder with a radius (r) and a height (h) has a surface area of:

52% Answer Correctly

2(π r2) + 2π rh

4π r2

π r2h

π r2h2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


5

Simplify (3a)(4ab) - (8a2)(5b).

59% Answer Correctly
52a2b
28ab2
-28a2b
91ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(3a)(4ab) - (8a2)(5b)
(3 x 4)(a x a x b) - (8 x 5)(a2 x b)
(12)(a1+1 x b) - (40)(a2b)
12a2b - 40a2b
-28a2b