When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 5c = -8c + z + 2 for c in terms of z.
| \(\frac{10}{11}\)z + \(\frac{6}{11}\) | |
| z + \(\frac{6}{13}\) | |
| -\(\frac{1}{4}\)z + \(\frac{1}{8}\) | |
| z + 3\(\frac{1}{2}\) |