ASVAB Math Knowledge Practice Test 509962

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2b + b = -5b + 5z - 2 for b in terms of z.

\(\frac{4}{7}\)z - \(\frac{2}{7}\)
\(\frac{2}{5}\)z - \(\frac{3}{5}\)
-z - 4\(\frac{1}{2}\)
4\(\frac{1}{2}\)z - 1