ASVAB Math Knowledge Practice Test 509998 Results

Your Results Global Average
Questions 5 5
Correct 0 3.25
Score 0% 65%

Review

1

Breaking apart a quadratic expression into a pair of binomials is called:

75% Answer Correctly

squaring

normalizing

deconstructing

factoring


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.


2

Solve for z:
-5z + 2 = -3 + 2z

60% Answer Correctly
\(\frac{5}{8}\)
1
\(\frac{5}{7}\)
\(\frac{3}{7}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-5z + 2 = -3 + 2z
-5z = -3 + 2z - 2
-5z - 2z = -3 - 2
-7z = -5
z = \( \frac{-5}{-7} \)
z = \(\frac{5}{7}\)


3

If side x = 8cm, side y = 13cm, and side z = 7cm what is the perimeter of this triangle?

85% Answer Correctly
28cm
22cm
33cm
21cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 8cm + 13cm + 7cm = 28cm


4

If c = 2 and z = -1, what is the value of 6c(c - z)?

69% Answer Correctly
36
325
-624
-198

Solution

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

6c(c - z)
6(2)(2 + 1)
6(2)(3)
(12)(3)
36


5

Solve -6b + 9b = -5b - 4y - 9 for b in terms of y.

35% Answer Correctly
\(\frac{2}{7}\)y - 1\(\frac{2}{7}\)
-\(\frac{2}{3}\)y - 1\(\frac{1}{3}\)
-1\(\frac{1}{6}\)y - \(\frac{1}{6}\)
13y + 9

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

-6b + 9y = -5b - 4y - 9
-6b = -5b - 4y - 9 - 9y
-6b + 5b = -4y - 9 - 9y
-b = -13y - 9
b = \( \frac{-13y - 9}{-1} \)
b = \( \frac{-13y}{-1} \) + \( \frac{-9}{-1} \)
b = 13y + 9