ASVAB Math Knowledge Practice Test 510753

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve + 6b = -b + 7z - 8 for b in terms of z.

1\(\frac{1}{2}\)z - \(\frac{2}{5}\)
z - 8
\(\frac{5}{9}\)z - \(\frac{1}{3}\)
-\(\frac{3}{4}\)z - \(\frac{1}{4}\)