When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c - c = c + 2z - 4 for c in terms of z.
| \(\frac{3}{5}\)z - \(\frac{4}{5}\) | |
| -2z - \(\frac{1}{2}\) | |
| -\(\frac{1}{15}\)z + \(\frac{2}{15}\) | |
| -1\(\frac{5}{8}\)z - \(\frac{3}{4}\) |