ASVAB Math Knowledge Practice Test 511087 Results

Your Results Global Average
Questions 5 5
Correct 0 3.20
Score 0% 64%

Review

1

On this circle, line segment AB is the:

71% Answer Correctly

radius

circumference

chord

diameter


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


2

The dimensions of this cube are height (h) = 9, length (l) = 4, and width (w) = 7. What is the volume?

83% Answer Correctly
81
252
27
72

Solution

The volume of a cube is height x length x width:

v = h x l x w
v = 9 x 4 x 7
v = 252


3

Solve for c:
c2 - 17c + 38 = -5c + 3

49% Answer Correctly
1 or -6
5 or 7
-4 or -6
2 or -7

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

c2 - 17c + 38 = -5c + 3
c2 - 17c + 38 - 3 = -5c
c2 - 17c + 5c + 35 = 0
c2 - 12c + 35 = 0

Next, factor the quadratic equation:

c2 - 12c + 35 = 0
(c - 5)(c - 7) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 5) or (c - 7) must equal zero:

If (c - 5) = 0, c must equal 5
If (c - 7) = 0, c must equal 7

So the solution is that c = 5 or 7


4

Simplify (7a)(2ab) - (6a2)(4b).

62% Answer Correctly
90a2b
-10a2b
10ab2
38ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(7a)(2ab) - (6a2)(4b)
(7 x 2)(a x a x b) - (6 x 4)(a2 x b)
(14)(a1+1 x b) - (24)(a2b)
14a2b - 24a2b
-10a2b


5

Solve for z:
2z - 4 > 9 - 2z

55% Answer Correctly
z > -\(\frac{1}{3}\)
z > -\(\frac{2}{9}\)
z > 3\(\frac{1}{4}\)
z > -\(\frac{2}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

2z - 4 > 9 - 2z
2z > 9 - 2z + 4
2z + 2z > 9 + 4
4z > 13
z > \( \frac{13}{4} \)
z > 3\(\frac{1}{4}\)