| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.21 |
| Score | 0% | 64% |
If side x = 9cm, side y = 15cm, and side z = 9cm what is the perimeter of this triangle?
| 33cm | |
| 36cm | |
| 32cm | |
| 43cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 9cm + 15cm + 9cm = 33cm
If the area of this square is 4, what is the length of one of the diagonals?
| 2\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 9\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)
Which of the following statements about a triangle is not true?
exterior angle = sum of two adjacent interior angles |
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perimeter = sum of side lengths |
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sum of interior angles = 180° |
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area = ½bh |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.
Simplify (y + 5)(y - 7)
| y2 - 2y - 35 | |
| y2 - 12y + 35 | |
| y2 + 12y + 35 | |
| y2 + 2y - 35 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y + 5)(y - 7)
(y x y) + (y x -7) + (5 x y) + (5 x -7)
y2 - 7y + 5y - 35
y2 - 2y - 35
The dimensions of this trapezoid are a = 6, b = 5, c = 9, d = 6, and h = 5. What is the area?
| 30 | |
| 18 | |
| 36 | |
| 27\(\frac{1}{2}\) |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(5 + 6)(5)
a = ½(11)(5)
a = ½(55) = \( \frac{55}{2} \)
a = 27\(\frac{1}{2}\)