When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 4c = c + 3z - 8 for c in terms of z.
| \(\frac{1}{5}\)z - \(\frac{9}{10}\) | |
| 1\(\frac{1}{12}\)z - \(\frac{1}{2}\) | |
| -1\(\frac{3}{7}\)z - \(\frac{5}{7}\) | |
| -\(\frac{1}{2}\)z - 4 |