ASVAB Math Knowledge Practice Test 512265

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve c + 7c = -5c - 3z - 2 for c in terms of z.

-\(\frac{5}{6}\)z - 1
-1\(\frac{2}{3}\)z - \(\frac{1}{3}\)
1\(\frac{1}{9}\)z + \(\frac{1}{9}\)
\(\frac{3}{5}\)z + \(\frac{1}{2}\)